3x^2(2x^2+5x)-7(2x^2+5)=0

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Solution for 3x^2(2x^2+5x)-7(2x^2+5)=0 equation: 


Simplifying
3x2(2x2 + 5x) + -7(2x2 + 5) = 0

Reorder the terms:
3x2(5x + 2x2) + -7(2x2 + 5) = 0
(5x * 3x2 + 2x2 * 3x2) + -7(2x2 + 5) = 0
(15x3 + 6x4) + -7(2x2 + 5) = 0

Reorder the terms:
15x3 + 6x4 + -7(5 + 2x2) = 0
15x3 + 6x4 + (5 * -7 + 2x2 * -7) = 0
15x3 + 6x4 + (-35 + -14x2) = 0

Reorder the terms:
-35 + -14x2 + 15x3 + 6x4 = 0

Solving
-35 + -14x2 + 15x3 + 6x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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